Jede Halbierung erhöht die Flaschenanzahl um 1: Start: 1 Flasche, nach n Halbierungen: \(n+1\) Flaschen.
Related Articles
- Richtiger Weg: Wie oft kann man 729 halbieren, bis Volumen bei ≤1 pro Flasche liegt?
- Anzahl der Flaschen = Anzahl der Halbierungen, bis Volumen < 1.
- \(729 \times (1/2)^n < 1\) → \(2^n > 729\) → \(n > \log_2(729) ≈ 9.51\) → \(n = 10\) Halbierungen.
- Somit: 11 Flaschen, letzte fasst <1 ml.
- But the problem says: "filling into bottles that each hold half of the previous".
- Clarify: Likely means each subsequent holds half of *previous capacity*, not recursive.
Trending Articles
Why Flash FM is the REAL Villain of GTA Vice City?
Surviving The Coastal Highway The Long Dark: Your Ultimate Guide
How to Start a Merciless RimWorld Social War
Can You Really Cheat at Bagatelle? The Hidden Techniques Exposed
Mafia 2 Hidden Magazines: The Full Collection Guide
Shin Megami Tensei V: Vengeance—Is This DLC the Darkest Secret Yet?
XCOM 2 The Chosen: Why The Soldiers You Love Aren't Coming Back
Why Does Your RimWorld Colony Suddenly Turn On Each Other?
Mirror Me: The Doppelganger in the Dark
Why Are All Blue Stones Banned in Pro Play?